2v^2+2v+60=v^2+12v+36

Solution for 2v^2+2v+60=v^2+12v+36 equation:

2v^2+2v+60=v^2+12v+36

We move all terms to the left:

2v^2+2v+60-(v^2+12v+36)=0

We get rid of parentheses

2v^2-v^2+2v-12v-36+60=0

We add all the numbers together, and all the variables

v^2-10v+24=0

a = 1; b = -10; c = +24;
Δ = b2-4ac
Δ = -102-4·1·24
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2}{2*1}=\frac{8}{2}
=4
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2}{2*1}=\frac{12}{2}
=6
$